Subject: Firm-Lean W/Out Gym

From: DocOz Cracks Weight-Loss Code <[email-masked]>
Date: Fri, 31 Oct 2014 09:42:47 -0800

I've been at it for years...

Eat this, dont eat this... I ate a cupcake, now I have to starve for day. 
3 night ago after my kids went to sleep, I opened my kids Halloween candy early
and starting eating it. 

There I was, in tears... because I was feeding a craving I felt like I had no control over. 

Then the miracle happened, a re-play of DocOz's show cam on. 

Now... I lost the cravings, eating what I want and im down 5LBS already.

This is a clip from the episode I saw -> http://www.jjuareporting.com/infestation/fancy/totter/indices.htm

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 ${cursor} 
 Actually the explicit instantiation needs to be in a .cpp file which has access to the definitions for all of Foo's member functions, rather than in the header. Excellent answer: thank you! "the compiler needs to have access to the implementation of the methods, to instantiate them with the template argument (in this case int). If these implementations were not in the header, they wouldn't be accessible" But why is an implementation in the .cpp file not accessible to the compiler? A compiler can also access .cpp information, how else would it turn them into .obj files? EDIT: answer to this question is in the link provided I don't think this explains the question that clearly, the key thing is obviously related with the compilation UNIT which is not mentioned in this post  means the same than 'class' here ? structs and classes are equivalent with the exception that the default access modifier for classes is "private", while it is public for structs. There are some other tiny differen
 ces that you can learn by looking at this question.  when compiling some other .cpp file, the .cpp with the implementation is unknown (and might even not be available, think library) No, the members of a class are private by default, not protected. Use explicit instantiation otherwise you will get very slow builds soon.