Subject: Ford, BMW, chevy - Select your 2014

From: Car Clearence Lot <[email-masked]>
Date: Mon, 02 Jun 2014 11:06:38 -0700

Autos Below The Kelly Blue Book Value
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When you go to a dealership you have to wonder if they are really giving you the best price. Chances are they are not. They are playing a game with you because they are working on commission.

Don't wonder if your getting the best-price.
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Re: Car repair forum: 435734564356544
98 K3500 Chevrolet, 7.4L. installed rebuilt 7.4L, can"t get spark at plugs. Checked all grounds, have power to coil. Scan tool shows trouble code p0336.

Pink is 12 volts with key on 
Purple is sensor ground and will have less than 0.1 volts with key on while back probing connector. 
Yellow is sensor signal and should have 0-12 volts while back probing the connector and cranking the engine. If your using a volt meter the voltage is going to be averaged out depending on cranking speed. You can also turn the crank by hand to see the true 0 and 12 volt signal on a volt meter. HT is correct that an o scope is the best tool for viewing hall effect sensor signals. 

Can't know your exact logistics to deal with this for your Dad or how far it is. If a GM shop wasn't fruitful it needs another or another person there. This can't stay this way. 

I have a class foo that has bar as a member variable.

In another member function of the class, I'm writing a lambda function:

[bar](void){}
But I can't include bar in the capture list. Why is that?

What I see is a low mile truck for it's years and maybe (you have to say) a lot of poking around driving. I'm guilty of that and do purposely get out and take a good run as where I am is all slow driving for myself. 

So, if you can't be there with stuff to check things out yourself then it (depending on your situation) it needs another look at by another. Who can know? 

Haven't taken on anything in ages now. Would when I hear from friends or family but driving 3-4 hours to come to me is a waste and then go back with hopes that something doesn't crop up the delays a repair. 

Is it real knock as in ping, knock, pre-ignition and are you sure of that from afar? IDK - Hammer suggested fuel pressure of possible things. It's goofy but you say "Dad" and I think of an older person but that may not be the case. Just between the lines, old vehicle, low miles suggests it isn't going all over the place all the time. I haven't seen a true carbon build up in quite a while or heard of one. Then again locally and family I don't know anyone who only pokes around all the time. Carbon build up should burn off with HWY use by itself - some don't but not many and those need tricks to break it up and blow that out. Probably not the case by guess right now. 
http://www.recalls.gov/nhtsa.html

You have to scope out the situation of what you can do from afar. We are not right there so that's that......... Tom 

Only objects with automatic storage duration can be captured by a lambda in C++11 (i.e. local variables and function parameters). If you want the effect of capturing a non-static class data member, you can either capture the this pointer as in Danvil's answer:

auto f = [this]{ std::cout << a << std::endl; };
or cache the data member's value in a local variable and capture that:

auto a = this->a;
auto f = [a]{ std::cout << a << std::endl; };
which will be much more concise in C++14:

auto f = [a = this->a]{ std::cout << a << std::endl; };
The choice between these two options depends on whether you want to store the value a has right now or if you want to retrieve the value a has when the lambda is called. Note that in the case where this is captured you must ensure that the lifetime of the pointer object encloses the lifetime of the lambda a call to the lambda after the object is destroyed has undefined behavior. The more simple case that captures a copy of a is completely self-contained and has no such lifetime issues.

n 17.6.4.2.1/1 and 17.6.4.2.1/2 of the current draft standard restrictions are placed on specializations injected by users into namespace std.

The behavior of a C ++ program is undefined if it adds declarations or definitions to namespace std or to a namespace within namespace std unless otherwise specified. A program may add a template specialization for any standard library template to namespace std only if the declaration depends on a user-defined type and the specialization meets the standard library requirements for the original template and is not explicitly prohibited.

I cannot find where in the standard the phrase user-defined type is defined.

One option I have heard claimed is that a type that is not std::is_fundamental is a user-defined type, in which case std::vector<int> would be a user-defined type.

An alternative answer would be that a user-defined type is a type that a user defines. As users do not define std::vector<int>, and std::vector<int> is not dependent on any type a user defines, std::vector<int> is not a user-defined type.

A practical problem this impacts is "can you inject a specialization for std::hash for std::tuple<Ts...> into namespace std? Being able to do so is somewhat convenient -- the alternative is to create another namespace where we recursively build our hash for std::tuple (and possibly other types in std that do not have hash support), and if and only if we fail to find a hash in that namespace do we fall back on std.

However, if this is legal, then if and when the standard adds a hash specialization for std::tuple to namespace std, code that specialized it already would be broken, creating a reason not to add such specializations in the future.

While I am talking about std::vector<int> as a concrete example, I am trying to ask if types defined in std are ever user-defined type s. A secondary question is, even if not, maybe std::tuple<int> becomes a user-defined type when used by a user (this gets slippery: what then happens if something inside std defines std::tuple<int>, and you partial-specialize hash for std::tuple<Ts...>).

Prof. Stroustrup is very clear that any type that is not built-in is user-defined. See the second paragraph of section 9.1 in Programming Principles and Practice Using C++.

He even specifically calls out standard library types as an example of user-defined types. In other words, a user-defined type is any compound type.

As users do not define std::vector<int>, and std::vector<int> is not dependent on any type a user defines, std::vector<int> is not a user-defined type.

The logical counter argument is that users do define std::vector<int>. You see std::vector is a class template and as such has no direct representation in binary code.

In a sense it gets it binary representation through the instantiation of a type, so the very action of declaring a std::vector<int> object is what gives "soul" to the template (pardon the phrasing). In a program where noone uses a std::vector<int> this data type does not exist.

On the other hand, following the same argument, std::vector<T> is not a user defined type, it is not even a type, it does not exist; only if we want to (instantiate a type), it will mandate how a structure will be layed out but until then we can only argue about it in terms of structure, design, properties and so on.

Note

The above argument (about templates being not code but ... well templates for code) may seem a bit superficial but draws it's logic, from Mayer's introduction in A. Alexandrescu's book Modern C++ Design. The relative quote there, goes like this :

Eventually, Andrei turned his attention to the development of template-based implementations of popular language idioms and design patterns, especially the GoF[*] patterns. This led to a brief skirmish with the Patterns community, because one of their fundamental tenets is that patterns cannot be represented in code. Once it became clear that Andrei was automating the generation of pattern implementations rather than trying to encode patterns themselves, that objection was removed, and I was pleased to see Andrei and one of the GoF (John Vlissides) collaborate on two columns in the C++ Report focusing on Andrei's work.

The draft standard contrasts fundamental types with user-defined types in a couple of (non-normative) places.

The draft standard also uses the term "user-defined" in other contexts, referring to entities created by the programmer or defined in the standard library. Examples include user-defined constructor, user-defined operator and user-defined conversion.

These facts allow us, absent other evidence, to tentatively assume that the intent of the standard is that user-defined type should mean compound type, according to historical usage. Only an explicit clarification in a future standard document can definitely resolve the issue.

Note that the historical usage is not clear on types like int* or struct foo* or void(*)(struct foo****). They are compound, but should they (or some of them) be considered user-defined?
I have an awkward problem, due to inheriting a shedload of really, really badly formatted HTML.

Basically I have some table rows like this:

<tr class="odd">...</tr>
<tr class="odd">...</tr>
<tr class="odd">...</tr>
<tr class="even">...</tr>
<tr class="even">...</tr>
<tr class="even">...</tr>
<tr class="odd">...</tr>
<tr class="odd">...</tr>
<tr class="odd">...</tr>
And what I need is a jQuery selector that will give me the first element of each block of classes. Is that clear enough? I'm not sure how else to explain it.

So in the example case I would want rows 1, 4, and 7.

Ive done this so far by selecting every nth child, but Ive now realised this wont work as there wont always be the same number of rows in each block of classes.

Any help you guys can give it appreciated, as always :)