Subject: [Tsvwg]question about rfc1042 ,Page5

From: "li suozhu" <[email-masked]>
Date: Mon, 18 Sep 2006 17:11:46 +0800

Hi,list,
I have some question
about rfc1042 , Page5, line 253---line 261,

"   The minimum packet size used with ARP is 24 octets,
which is 20
(ARP with 2 octet hardware
addresses and 4 octet protocol
addresses)
+ 8 (LLC+SNAP header) = 24 octets (not including
the
MAC header).

In typical situations, the packet size
used with ARP is 32 octets,
which is 28
(ARP with 6 octet hardware addresses and 4
octet
protocol addresses) + 8 (LLC+SNAP
header) = 32 octets (not
including the
MAC header).
"
I can't understand why ' 20 + 8 ' is '
24 ' but not is  ' 28 ',and the same puzzle in 28 + 8 = 32

Cheers
Li

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